Nuprl Lemma : l_disjoint_member 4,23

T:Type, l1l2:T List, x:T. l_disjoint(T;l1;l2 (x  l1 (x  l2
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Definitionst  T, x:AB(x), (x  l), Prop, P & Q, A, P  Q, False, l_disjoint(T;l1;l2), True
Lemmasnot wf, l member wf

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